VERSION 2 CE IIT KHARAGPUR PDF

Course Contents. ||. Department Details. ||. Message Board. ||. Module 1 · Module 2 · Module 3 · Module 4 · Module 5 · Module 6 · Module 7. Structural Analysis 2. View Test Prep – m8l19 from CI 11 at JNTU College of Engineering. Module 8 Reinforced Concrete Slabs Version 2 CE IIT, Kharagpur Lesson 19 Two-way. Version 2 CE IIT Kharagpur Typical cross section through the embankment portion from CIVIL at Indian Institute of Technology, Kharagpur.

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Version 2 CE IIT, Kharagpur | EduRev Notes

The nmbering of joints kharagpurr members are shown in Fig. Sort B Sort C. The maximm cable tension occrs at Band the minimm cable tension occrs dy atc where andtc H 7.

It is as important for the More information. The government wants to redce drink-driving. Module Advanced Structural Analysis Prof. The eqivalent joint loads de to sort settlement and external loading are shown in Fig.

The flow may be analysed by considering a small portion of flow domain as shown in Figure However, there is a small difference. Analyse lane frames by the direct versioj matrix method. Imose bondary conditions on the load-dislacement relation. The eqivalent joint loads de to sort settlement are shown in Fig. Since, in the original arch strctre, there is no horizontal dislacement, now aly a horizontal force H as shown in Fig.

Version 2 CE IIT, Kharagpur | nuru ahmed –

Evalate the horizontal thrst and the maximm bending moment in iharagpur arch. A cable of niform cross section is sed to sort the loading shown in Fig.

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Unlike rigid strctres, deformable strctres ndergo changes in their shae according to externally alied loads. T k T k ‘ T The assembled global stiffness matrix K is of the order9 9. What are Structural Deflections?

The ossible dislacements at each node of the member are: Few nmerical roblems are solved by direct stiffness method to illstrate the rocedre discssed. Consider a three hinged arch sbjected to a concentrated forcep as shown in Fig. It is observed in the last lesson that, the cable takes the shae of the loading and this shae is termed as fniclar shae.

Writing the load dislacement relation for the entire continos beam. However dead weight of the cable is neglected in the resent analysis.

Computation of forces and moments Problem 5: Already Have an Account? Students will be able to: Comte reactions de to following sort settlements. In the case of lane frames, members are oriented in different directions and hence before forming the global stiffness matrix it is necessary to refer all the member stiffness matrices to the same set of axes.

The fixed end actions de to sort settlement are, M F Verwion EI where is the chord rotation and is taken ve if the rotation is conterclockwise. The rocedre to imose bondary conditions on the loaddislacement relation is discssed. In earlier days arches were constrcted sing stones and bricks. Hence the gradient of water table in unconfined flow is not constant, it increases in the direction of flow.

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The oharagpur may be incomplete. In the end, a few roblems are solved to illstrate the methodology. Until the beginning of the th centry, arches and valts were commonly sed to san between walls, iers or other sorts. Primary objective of the force method is to More information. In this lesson, few continos beam roblems are solved nmerically by direct stiffness method.

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Overview Flows along rivers, throgh pipes and irrigation channels enconter resistance that is proportional More information. Similarly the relation between shear force, bending moment with translation along y ‘ axis and rotation abot z’ axis are given in lesson 7. Taking moment abot the hinge of all the forces acting on either side of the hinge can set the reqired eqation. vefsion

Version 2 CE IIT, Kharagpur

Sbstitting the vale of x in eqationthe maximm bending moment is obtained. Cable is a fniclar strctre.

Taking moment of all the forces abot hingea, yields by P P. In sch cases cable is assmed to be niformly loaded. Cable sbjected to Concentrated oads As stated earlier, the cables are considered to be erfectly flexible no flexral stiffness and inextensible.

New approaches in Eurocode 3 efficient global structural design New approaches in Eurocode 3 efficient global structural design Part 1: What is the definition of eqilibrim? Verslon we get a simly sorted crved beam as shown in Fig. The nmbering of the joints and members are shown in Fig. The concept of More information. This problem was solved by J. The member is assmed to have niform flexral rigidity EI and niform khaagpur rigidityea for sake of simlicity.